Consider two vectors A=3i - 1j and B = - i - 5j, how do you calculate $abs(A-B)$ ?

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Answer 1 · 2015-12-09T19:28:03

$|A-B|=sqrt32$

$A-B= A+(-B)$

$=3 hati-hatj+(hati+5hatj)$

$=4hati-4hatj$

$therefore|A-B|=|4hati-4hatj|$

$=sqrt(4^2+4^2)$

$=sqrt32$

Consider two vectors A=3i - 1j and B = - i - 5j, how do you calculate abs(A-B)abs(A-B)?