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Consider two vectors A=3i - 1j and B = - i - 5j, how do you calculate #abs(A-B)#?

1 Answer

Dec 9, 2015

#|A-B|=sqrt32#

Explanation:

#A-B= A+(-B)#

#=3 hati-hatj+(hati+5hatj)#

#=4hati-4hatj#

#therefore|A-B|=|4hati-4hatj|#

#=sqrt(4^2+4^2)#

#=sqrt32#

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