Consider the following reaction: Li_2S(aq) + Co(NO_3)_2 (aq) -> 2LiNO_3(aq) + CoS(s). What volume of 0.160 mol*L^-1 Li_2S, solution is required to completely react with 0.130 mol*L^-1 Co(NO_3)_2?

1 Answer
anor277
May 6, 2018

Well the reaction relies on the brick-like solubility of transition-metal sulfides.

Explanation:

We gots...

Li_2S(aq) + Co(NO_3)_2(aq) rarr CoS(s)darr + 2LiNO_3(aq)..

Else we could write the net ionic equation:

Co^(2+) + S^(2-) rarr CoS(s)darr

And so we gots with respect to Co^(2+) 0.130*mol*L^-1...

0.130*mol*L^-1xx100*mLxx10^-3*L*mL^-1=0.0130*mol...the volume of the cobalt ion solution was interpolated.

And given the 1:1 stoichiometry....we take the quotient...

(0.0130*mol)/(0.160*mol*L^-1)xx1000*mL*L^-1=81.3*mL of the lithium sulfide solution. Ad please note that I had to interpolate the concentration of lithium sulfide.

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