(complexe numbers) Show that? Thank you!

Is z ∈ C \ {0},
than is |z|/z a square root of z^-/z

1 Answer
Sanjay VN
Jan 15, 2018

yes

Explanation:

multiply and divide RHS by z
so we get
zz^-/(z)^2 = |z|^2/(z)^2 = (|z|/z)^2
hence
|z|/z will be a square root of the z^-/z which is (LHS)^2
hope u find it helpful :)

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