Can you please find ''x'' ?

2^x=302x=30

1 Answer
Jun 18, 2018

x = 4.91x=4.91

Explanation:

We have this equation

2^x = 302x=30

We add loglog to both sides

log2^x = log 30log2x=log30

Using one of the rules of logarithms, we move the xx in front

xlog2 = log 30xlog2=log30

Divide both sides by log 2log2

x = log30/log2x=log30log2

Calculate the final answer

x = 4.91x=4.91