Can someone help me solve this problem with law of sines?

Question

842 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-02-27T05:09:24

Answer is $5.9$

As $m/_A=15^@$ and $m/_B=20^@$ , $m/_C=180^@-15^@-29^@-145^@$

Now according to sine law,

$a/sinA=b/sinB=c/sinC$ , here $a=BC$ , $b=AC$ and $c=AB$

Hence $a/(sin15^@)=b/(sin20^@)=10/(sin145^@)$

and $AC=b=10/(sin145^@)xxsin20^@$

= $10/0.5736xx0.3420=5.962~=5.9$

Hence answer is $5.9$