Can someone help me solve for this side?

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Can someone help me solve for this side?

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Answer 1 · 2018-04-24T17:51:33

$X Z = 55$ $XZ=55$

Explanation:

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Angle $∠ Y X Z$ $/_YXZ$ is facing arc $Y Z$ $YZ$ .

Angle $∠ X Y Z$ $/_XYZ$ is facing arc $X Z$ $XZ$ .

Arc $Y Z$ $YZ$ and arc $X Z$ $XZ$ are equal to each other. Therefore,

$∠ Y X Z = ∠ X Y Z$ $/_YXZ = /_XYZ$

This means that triangle $DeltaXYZ$ is an isoceles triangle with sides $XZ$ and $YZ$ equal to each other. As such, we can put their measures equal to each other and solve for $x$ :

$6x+10=8x-5$

$2x=15$

$x=15/2$

Now, we can plug this value in for $x$ in the measure of $XZ$ :

$XZ=6x+10=6(15/2)+10=45+10=55$

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Can someone help me solve for this side?

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