Can someone explain to me how you would get (1+cot^2X) from this?

Question

#cot^2X*csc^2X#

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Answer 1 · 2018-03-31T13:21:56

This is not an identity.

#cot^2(x)*csc^2(x)=1+cot^2(x)#

Let #x=pi/6#

#cot^2(pi/6)*csc^2(pi/6)=1+cot^2(pi/6)#

#3xx4=1+4color(white)(88888)# FALSE

Therefore:

#cot^2(x)*csc^2(x)!=1+cot^2(x)#