Calculate the mass of oxygen in a molecule of #"CO"_2# by using percentage composition? please help
1 Answer
Explanation:
The first thing you need to do here is to figure out the mass of oxygen in
Now, carbon dioxide has a molar mass of
You know that
- one mole of carbon,
#1 xx "C"# - two moles of oxygen,
#2 xx "O"#
Oxygen has a molar mass of
This means that if you take
#2 color(red)(cancel(color(black)("moles O"))) * "16.0 g"/(1color(red)(cancel(color(black)("mole O")))) = "32.0 g O"#
This means that
#100color(red)(cancel(color(black)("g CO"_2))) * "32.0 g O"/(44.01color(red)(cancel(color(black)("g CO"_2)))) = "72.7 g O"#
Therefore, carbon dioxide has a percent composition of
Now, you must determine the mass of oxygen present in a single molecule of carbon dioxide. Start by figuring out the mass of a single molecule of carbon dioxide.
To do that, use Avogadro's constant, which tells you that
#color(blue)(ul(color(black)("1 mole CO"_2 = 6.022 * 10^(23)"molecules CO"_2)))#
So, you know what
#"1 mole CO"_2 = "44.01 g" = 6.022 * 10^(23)"molecules CO"_2#
which means that
#1 color(red)(cancel(color(black)("molecule CO"_2))) * "44.01 g"/(6.022 * 10^(23)color(red)(cancel(color(black)("molecules CO"_2))))#
# = 7.31 * 10^(-23)"g"#
Now you can use the percent composition of carbon dioxide to find the mass of oxygen present in
#7.31 * 10^(-23) color(red)(cancel(color(black)("g CO"_2))) * "72.7 g O"/(100color(red)(cancel(color(black)("g CO"_2)))) = color(darkgreen)(ul(color(black)(5.3 * 10^(-23)"g O")))#
I'll leave the answer rounded to two sig figs.