Calculate the mass in kilograms of $2.6xx10^23$ molecules of $"SO"_2$ ?

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Answer 1 · 2018-06-10T12:04:33

$"0.028 kg"$

We were given $2.6 xx 10^23$ molecules of $"SO"_2$ . That means that

$N = 2.6 xx 10^23 \ "molecules"$

Use

$n ("number of moles") = N/(N_A ("Avogadro's constant"))$

to get

$n = (2.6 xx 10^23\ "molecules") / (6.02 xx 10^23\ "molecules/mol") = "0.432 moles"$

Now use

$m = n xx M ("molar mass")$

to get

$m = "0.432 mol" xx "64.066 g/mol" = "27.677 g"$

So

$m ("in kilograms") = "27.677 g" / (10^3 \ "g/kg") = "0.028 kg"$

Calculate the mass in kilograms of 2.6xx10^232.6xx10^23 molecules of "SO"_2"SO"_2 ?