Calcium carbonate, $CaCO_3$ has a Ksp value of $1.4 x 10^-8$ , what is the solubility of $CaCO_3$ ?

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Answer 1 · 2016-08-24T08:05:18

$CaCO_3(s) rightleftharpoons Ca^(2+) + CO_3^(2-)$

$K_(sp)=[Ca^(2+)][CO_3^(2-)]$ $=$ $1.4xx10^-8$ .

If we call the solubility $S$ , then $S=[Ca^(2+)]=[CO_3^(2-)]$ , and,

$K_(sp)=[Ca^(2+)][CO_3^(2-)]$ $=$ $1.4xx10^-8$ $=$ $S^2$

So $Ca^(2+)$ $=$ $sqrt{K_"sp"}$ $=$ $sqrt(1.4xx10^-8)$ $=$ $1.18xx10^(-4)$ $mol*L^-1$ .

$"Solubility"$ $=$ $1.18xx10^-4xx100.09*g*mol^-1$ $=$ $??g*L^-1$

Calcium carbonate, CaCO_3CaCO_3 has a Ksp value of 1.4 x 10^-81.4 x 10^-8, what is the solubility of CaCO_3CaCO_3?