Ca(OH)2 + H3PO4 = CaHPO4 + 2H2O From This Chemical Equitation Calculate The Equivalent Weight Of H3PO4 ?? Answer The Question With Explanation !

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Answer 1 · 2018-07-15T06:24:49

The equivalent weight is $= 49$ $=49$

The reaction is

$C a {(O H)}_{2} + H_{3} P O_{4} \to C a H P O_{4} + 2 H_{2} O$ $Ca(OH)_2 + H_3PO_4rarrCaHPO_4+2H_2O$

In this reaction

$H_{3} P O_{4} \to H P O_{4}^{2 -} + 2 H^{+}$ $H_3PO_4rarrHPO_4^(2-)+2H^+$

Orthophosphoric acid leaves $2$ $2$ hydrogen ions.

Hence, its valency factor is $= 2$ $=2$

$Equivalent weight = \frac{Molecular Weight}{2}$ $"Equivalent weight " = "Molecular Weight "/2$

Molecular weight $= 1 \cdot 3 + 31 + 4 \cdot 16 = 98$ $=1*3+31+4*16=98$

Therefore,

The equivalent weight is $= \frac{98}{2} = 49$ $=98/2=49$