$C_2H_4 + 3O_2 -> 2CO_2 +2H_2O$ . If you start with 45 grams of ethylene ( $C_2H_4$ ), how many grams of carbon dioxide will be produced?

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Answer 1 · 2017-03-29T18:20:02

141.416g

$"No. of mol of ethylene"=45/(2*12+4*1)~~1.607mol$

$"No. of mol of "CO_2" produced"=2*1.607=3.214mol$

$"Mass of "CO_2"=3.214*(12+2*16)=141.416g$

C_2H_4 + 3O_2 -> 2CO_2 +2H_2OC_2H_4 + 3O_2 -> 2CO_2 +2H_2O. If you start with 45 grams of ethylene (C_2H_4C_2H_4), how many grams of carbon dioxide will be produced?