Blood types A, B, O, and AB have percentages 40%, 20%, 30% and 10%. If two individuals are chosen at random, assuming independence, how do you find probability that both blood type A?

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Answer 1 · 2016-09-11T13:07:48

$0.16$ $0.16$ .

Let, $A_{1}$ $A_1$ be the Event that the randomly chosen First Individual has

the Blood Group $A$ $A$ , and, let, $A_{2}$ $A_2$ be for the Second Individual.

$:." The Reqd. Prob.="P(A_1nnA_2)$ .

But, $A_1 and A_2$ are Independent Events, therefore,

$P(A_1nnA_2)=P(A_1)*P(A_2).............................................(star)$ .

Since, 40% of Individuals have Blood Group A, clearly,

$P(A_1)=P(A_2)=40/100=0.4$

Hence, by $(star), "the Reqd. Prob."=0.4xx0.4=0.16$ .