Are 21, 27 and 36 an example of a Pythagorean triplet?

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Answer 1 · 2015-07-01T08:18:25

No, the following numbers do not form a Pythagorean triplet.

If three sides $a,b,c$

in which $color(blue)(a)> color(green)(b,c$ are supposed to be a Pythagorean triplet they should satisfy the Pythagoras theorem:

$color(blue)(a^2) = color(green)(b^2 +c^2$

Here $color(blue)(a=36, color(green)(b = 27, c=21$

As per theorem:

$color(blue)(a^2$ should be equal to $color(green)( b^2 +c^2$

But the sum doesn't follow the Pythagoras theorem, as:

$36^2 != 27^2 + 21^2$
$1296 != 729 + 441$
$1296!=1170$

So, the following numbers do not form a Pythagorean triplet.