Answer ???

Question

Answer ???

1 Answer

Impact of this question

997 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-13T11:06:53

See below.

Explanation:

$[A B D]$ $[ABD]$ is an isosceles triangle
$[A B E]$ $[ABE]$ is an isosceles triangle also

then calling

$ˆ B A E = a$ $hat(BAE) = a$
$ˆ B E A = a$ $hat(BEA) = a$
$ˆ C A D = b = 10^{\circ}$ $hat(CAD)= b = 10^@$
$ˆ B D A = d$ $hat(BDA)=d$
$ˆ B A D = d$ $hat(BAD)=d$
$ˆ A F E = c$ $hat(AFE)=c$

we have for triangles $[A F E]$ $[AFE]$ and $[B F D]$ $[BFD]$ respectively

${(b+c+a=180^@),(x+c+d = 180^@),(d=a-b):}$

now substituting and subtracting the corresponding sides we have

$x -2b=0$ or

$x = 20^@$

enter image source here

NOTE:

This can be quickly concluded also by considering over the circle, that the angle $hat(CAD) = hat(EBC)/2$

Science

Math

Humanities

... and beyond

Answer ???

1 Answer

Explanation:

Related questions

Impact of this question