An object with a mass of 8 kg8kg is traveling in a circular path of a radius of 12 m12m. If the object's angular velocity changes from 2 Hz2Hz to 7 Hz7Hz in 6 s6s, what torque was applied to the object?

1 Answer
Nov 11, 2017

"6031.86 Nm"6031.86 Nm of torque was applied to object.

Explanation:

Torque is rate of change of angular momentum.

T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t

T = ("8 kg × (12 m)"^2 × 2 π (7 - 2) "Hz")/"6 s" = "6031.86 Nm"