An object with a mass of 8 kg8kg is traveling in a circular path of a radius of 12 m12m. If the object's angular velocity changes from 5 Hz5Hz to 4 Hz4Hz in 5 s5s, what torque was applied to the object?

1 Answer
Feb 22, 2016

L=230,4 N*mL=230,4Nm

Explanation:

L=alpha*IL=αI
L:" Torque"L: Torque
alpha:" angular acceleration"α: angular acceleration
I:" moment of inertia of object"I: moment of inertia of object
alpha=(Delta w)/(Delta t)α=ΔwΔt
alpha=(2*pi(4-5))/5
alpha=-(2*pi)/5
I=m*r^2
I=8*12^2=144*8=1152
L=-(1152*2*pi)/5
L=230,4 N*m