An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $32 m$ $32 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?

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An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $32 m$ $32 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-12-09T12:08:51

This is effectively a moments question.

Explanation:

The mass exerts a moment in one direction (we can assume it is clockwise) equal to the product of its weight (m x g) and the perpendicular distance (d). In this case the clockwise moment (taking g = 9.8 N/kg) will be:

$M_{c} = m \times g \times d = 8 \times 9.81 \times 32$ $M_c = m xx g xx d = 8 xx 9.81 xx 32$

$M_{c} = 2500 N m$ $M_c = 2500 Nm$ (to 2 s.f as given in the data)

To balance this and attain equilibrium there must be an equal and opposite moment. We are told that the distance on the other side must be 24m and asked to solve for the weight, w ( = m x g)

$w = \frac{M_{a}}{d} = \frac{2500}{24}$ $w = (M_a)/d = 2500/24$

$w = 104.64$ $w = 104.64$ N which I’d probably quote as 105N

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An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $32 m$ $32 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?

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Explanation:

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An object with a mass of 8 kg8kg8 kg is hanging from an axle with a radius of 32 m32m32 m. If the wheel attached to the axle has a radius of 24 m24m24 m, how much force must be applied to the wheel to keep the object from falling?

1 Answer

Explanation:

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An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $32 m$ $32 m$ . If the wheel attached to the axle has a radius of $24 m$ $24 m$ , how much force must be applied to the wheel to keep the object from falling?