An object with a mass of $8 k g$ $8 kg$ is hanging from an axle with a radius of $16 m$ $16 m$ . If the wheel attached to the axle has a radius of $48 m$ $48 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-05-02T08:35:13

The force is $= 26.1 N$ $=26.1N$

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The load L=(8g)N#

Radius of axle $r = 16 m$ $r=16m$

Radius of wheel $R = 48 m$ $R=48m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 48 = 8 \cdot g \cdot 16$ $F*48=8*g*16$

$F = \frac{8 \cdot g \cdot 16}{48} = \frac{8}{3} g = 26.1 N$ $F=(8*g*16)/48=8/3g=26.1N$

An object with a mass of 8 kg8kg8 kg is hanging from an axle with a radius of 16 m16m16 m. If the wheel attached to the axle has a radius of 48 m48m48 m, how much force must be applied to the wheel to keep the object from falling?