An object with a mass of $8 g$ is dropped into $20 mL$ of water at $0^@C$ . If the object cools by $15 ^@C$ and the water warms by $60 ^@C$ , what is the specific heat of the material that the object is made of?

Question

1998 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-13T12:59:26

The specific heat is $=41.86kJkg^-1K^-1$

The heat is transferred from the hot object to the cold water.

For the cold water, $Delta T_w=60ºC$

For the object $DeltaT_o=15ºC$

$m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)$

$C_w=4.186kJkg^-1K^-1$

Let, $C_o$ be the specific heat of the object

$0.008*C_o*15=0.020*4.186*60$

$C_o=(0.020*4.186*60)/(0.008*15)$

$=41.86kJkg^-1K^-1$

An object with a mass of 8 g8 g is dropped into 20 mL20 mL of water at 0^@C0^@C. If the object cools by 15 ^@C15 ^@C and the water warms by 60 ^@C60 ^@C, what is the specific heat of the material that the object is made of?