An object with a mass of #70 g# is dropped into #700 mL# of water at #0^@C#. If the object cools by #36 ^@C# and the water warms by #8 ^@C#, what is the specific heat of the material that the object is made of?

1 Answer
ali ergin
Feb 8, 2016

#c_o=0,002#

Explanation:

#m=700 m g=0,7 g " mass of water"#
#Q_w=m*c*Delta t#
#Q_w=0,7*1*8=5,6 Cal " Heat gained by water"#
#Q_o=m_o*c_o*Delta t_o#
#Q_o=70* c_o*36#
#Q_w=Q_o#
#70*c_o*36=5,6#
#c_o=(5,6)/(70*36)#
#c_o=(5,6)/2520#
#c_o=0,002#

Related questions
See all questions in Specific Heat
Impact of this question
1298 views around the world
You can reuse this answer
Creative Commons License