An object with a mass of 60 g is dropped into 900 mL of water at 0^@C. If the object cools by 40 ^@C and the water warms by 16 ^@C, what is the specific heat of the material that the object is made of?

1 Answer
Shwetank Mauria
Mar 6, 2016

Specific heat of the material that the object is 6.

Explanation:

In such cases heat lost by one equals heat gained by other. Heat lost / gained is given by product of mass m, specific heat s (which is 1 for water) and change in temperature,

Let the specific heat of the mass of 60g, which cools by 40^oC be s. Hence heat lost is 60xx40xxs calories.

900mL of water means 900g and it warms by 16∘C. Hence heat gained by it is 900xx16=14400 calories.

Hence 60xx40xxs=14400 or x=14400/(60xx40)=6

Hence, specific heat of the material that the object is 6.

Related questions
See all questions in Specific Heat
Impact of this question
1680 views around the world
You can reuse this answer
Creative Commons License