An object with a mass of #6 kg# is revolving around a point at a distance of #8 m#. If the object is making revolutions at a frequency of #6 Hz#, what is the centripetal force acting on the object?

1 Answer
JMicheli
Jul 10, 2016

The force acting on the object is #6912pi^2# Newtons.

Explanation:

We'll start by determining the velocity of the object. Since it is revolving in a circle of radius 8m 6 times per second, we know that:

#v = 2pir*6#

Plugging in values gives us:

#v = 96 pi# m/s

Now we can use the standard equation for centripetal acceleration:

#a = v^2/r#
#a = (96pi)^2/8#
#a = 1152pi^2# m/s^2

And to finish the problem we simply use the given mass to determine the force needed to produce this acceleration:
#F = ma#
#F = 6*1152pi^2#
#F = 6912pi^2# Newtons

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