An object with a mass of $6 k g$ $6 kg$ is hanging from an axle with a radius of $9 m$ $9 m$ . If the wheel attached to the axle has a radius of $18 m$ $18 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2018-01-14T07:19:58

The force is $= 29.4 N$ $=29.4N$

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The load is $L = 6 g N$ $L=6gN$

The radius of the axle is $r = 9 m$ $r=9m$

The radius of the wheel is $R = 18 m$ $R=18m$

The effort is $= F N$ $=FN$

The acceleration due to gravity is $g = 9.8 m s^{- 2}$ $g=9.8ms^-2$

Taking moments about the center of the axle

$F \cdot 18 = 6 g \cdot 9$ $F*18=6g*9$

$F = \frac{6 g \cdot 9}{18} = 29.4 N$ $F=(6g*9)/18=29.4N$

The force is $F = 29.4 N$ $F=29.4N$

An object with a mass of 6 kg6kg6 kg is hanging from an axle with a radius of 9 m9m9 m. If the wheel attached to the axle has a radius of 18 m18m18 m, how much force must be applied to the wheel to keep the object from falling?