An object with a mass of $6 k g$ $6 kg$ is hanging from an axle with a radius of $24 m$ $24 m$ . If the wheel attached to the axle has a radius of $8 m$ $8 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-04-29T06:24:05

The force is $= 176.4 N$ $=176.4N$

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The load L=(6g)N#

Radius of axle $r = 24 m$ $r=24m$

Radius of wheel $R = 8 m$ $R=8m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 8 = 6 \cdot g \cdot 24$ $F*8=6*g*24$

$F = \frac{6 \cdot g \cdot 24}{8} = 18 g = 176.4 N$ $F=(6*g*24)/8=18g=176.4N$

An object with a mass of 6 kg6kg6 kg is hanging from an axle with a radius of 24 m24m24 m. If the wheel attached to the axle has a radius of 8 m8m8 m, how much force must be applied to the wheel to keep the object from falling?