An object with a mass of #50 g# is dropped into #450 mL# of water. If the object cools by #25 ^@C# and the water warms by #10 ^@C#, what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-03-12T03:17:20

Heat lost by the body = heat gained by water
#50gxxsxx25^oC =450mlxx1g/(ml)xx1calg^-1^oC^-1xx10^oC#
#s=3.6calg^-1 ^oC^-1#