An object with a mass of 50 g50g is dropped into 450 mL450mL of water. If the object cools by 25 ^@C25C and the water warms by 10 ^@C10C, what is the specific heat of the material that the object is made of?

1 Answer
Mar 12, 2016

Heat lost by the body = heat gained by water
50gxxsxx25^oC =450mlxx1g/(ml)xx1calg^-1^oC^-1xx10^oC50g×s×25oC=450ml×1gml×1calg1^oC1×10oC
s=3.6calg^-1 ^oC^-1s=3.6calg1^oC1