An object with a mass of #50 g# is dropped into #300 mL# of water at #0^@C#. If the object cools by #80 ^@C# and the water warms by #5 ^@C#, what is the specific heat of the material that the object is made of?

Question

1508 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-25T09:23:40

Specific heat of the material that the object is made of is #0.375#.

Let the specific heat of the object of mass #50g# be #s#. As the object cools by #80^oC#, heat lost by it s

#50xx80xxs=4000s#

Heat gained by water (assuming container has not gained any heat) is #300xx5xx1=1500# - as each #mL# of water is #1g#.

Hence #4000s=1500# and #s=1500/4000=0.375#