An object with a mass of $50 g$ is dropped into $300 mL$ of water at $0^@C$ . If the object cools by $80 ^@C$ and the water warms by $5 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-06-25T09:23:40

Specific heat of the material that the object is made of is $0.375$ .

Let the specific heat of the object of mass $50g$ be $s$ . As the object cools by $80^oC$ , heat lost by it s

$50xx80xxs=4000s$

Heat gained by water (assuming container has not gained any heat) is $300xx5xx1=1500$ - as each $mL$ of water is $1g$ .

Hence $4000s=1500$ and $s=1500/4000=0.375$

An object with a mass of 50 g50 g is dropped into 300 mL300 mL of water at 0^@C0^@C. If the object cools by 80 ^@C80 ^@C and the water warms by 5 ^@C5 ^@C, what is the specific heat of the material that the object is made of?