An object with a mass of $4 kg$ , temperature of $244 ^oC$ , and a specific heat of $33 (KJ)/(kg*K)$ is dropped into a container with $16 L$ of water at $0^oC$ . Does the water evaporate? If not, by how much does the water's temperature change?

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Answer 1 · 2017-03-17T09:45:55

The water evaporates.

The heat is transferred from the hot object to the cold water.

Let $T=$ final temperature of the object and the water

For the cold water, $Delta T_w=T-0=T$

For the object $DeltaT_o=244-T$

$m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)$

$C_w=4.186kJkg^-1K^-1$

$C_o=33kJkg^-1K^-1$

$4*33*(244-T)=16*4.186*T$

$244-T=(16*4.186)/(132)*T$

$244-T=0.51T$

$1.51T=244$

$T=244/1.51=161.6ºC$

As $T>100ºC$ , the water evaporates.

An object with a mass of 4 kg4 kg, temperature of 244 ^oC244 ^oC, and a specific heat of 33 (KJ)/(kg*K)33 (KJ)/(kg*K) is dropped into a container with 16 L 16 L of water at 0^oC 0^oC . Does the water evaporate? If not, by how much does the water's temperature change?