An object with a mass of $4 g$ is dropped into $650 mL$ of water at $0^@C$ . If the object cools by $300 ^@C$ and the water warms by $2 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2017-11-20T12:33:13

The specific heat is $=4.53kJkg^-1K^-1$

The heat is transferred from the hot object to the cold water.

For the cold water, $Delta T_w=2ºC$

For the object $DeltaT_o=300ºC$

$m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)$

$C_w=4.186kJkg^-1K^-1$

Let, $C_o$ be the specific heat of the object

The mass of the object is $m=0.004kg$

$0.004*C_o*300=0.650*4.186*2$

$C_o=(0.650*4.186*2)/(0.004*300)$

$=4.53kJkg^-1K^-1$

An object with a mass of 4 g4 g is dropped into 650 mL650 mL of water at 0^@C0^@C. If the object cools by 300 ^@C300 ^@C and the water warms by 2 ^@C2 ^@C, what is the specific heat of the material that the object is made of?