An object with a mass of $4 g$ is dropped into $250 mL$ of water at $0^@C$ . If the object cools by $120 ^@C$ and the water warms by $2 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2017-02-16T16:30:53

The specific heat of the material is $=1,042 Kcalkg^-1°C^-1$

The heat transferred from the hot object, is equal to the heat absorbed by the cold water.

For the cold water, $Delta T_w=2ºC$

For the object $DeltaT_o=120ºC$

$M_o C_o (DeltaT_o) = Mw C_w (Delta_w)$

$C_w=1Kcalkg^-1ºC^-1$

$0,004 C_o120 = 0,250* 1 *2$

$C_o = 0.5/ 0.48 = 1,042 Kcalkg^-1°C^-1$

An object with a mass of 4 g4 g is dropped into 250 mL250 mL of water at 0^@C0^@C. If the object cools by 120 ^@C120 ^@C and the water warms by 2 ^@C2 ^@C, what is the specific heat of the material that the object is made of?