An object with a mass of 32 g is dropped into 480 mL of water at 0^@C. If the object cools by 120 ^@C and the water warms by 9 ^@C, what is the specific heat of the material that the object is made of?

1 Answer
Feb 17, 2016

c_o=1,125 " may be ammonia liquid"

Explanation:

Q_o=m_o*c_o*Delta t_o" Heat given by object a mass of 32 g"
c_o": specific heat of object"
Q_o=32*c_o*120
Q_o=3840*c_o
Q_w=m_w*c_w*Delta t_w" Heat gained by water"
V_=480 m ; m_=480 g ; c_w=1
Q_w=480*1*9
Q_w=4320 Cal
Q_o=Q_w " conversation of energy"
3840*c_o=4320
c_o=4320/3840
c_o=1,125 " may be ammonia liquid"