An object with a mass of #32 g# is dropped into #250 mL# of water at #0^@C#. If the object cools by #160 ^@C# and the water warms by #12 ^@C#, what is the specific heat of the material that the object is made of?
1 Answer
Jul 4, 2016
0,586 kcal/kg K
Explanation:
Ms x Cps x deltaT s = Mw x Cpw X deltaTw
Cps= 0,25 Kg x 1 Kcal/kg K x 12 K /( 0,032 kg x 160 K) = 0586 Kcal/kg K
