An object with a mass of $32 g$ is dropped into $250 mL$ of water at $0^@C$ . If the object cools by $160 ^@C$ and the water warms by $12 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2016-07-04T03:15:19

0,586 kcal/kg K

Ms x Cps x deltaT s = Mw x Cpw X deltaTw

Cps= 0,25 Kg x 1 Kcal/kg K x 12 K /( 0,032 kg x 160 K) = 0586 Kcal/kg K

An object with a mass of 32 g32 g is dropped into 250 mL250 mL of water at 0^@C0^@C. If the object cools by 160 ^@C160 ^@C and the water warms by 12 ^@C12 ^@C, what is the specific heat of the material that the object is made of?