An object with a mass of $3 kg$ is traveling in a circular path of a radius of $7 m$ . If the object's angular velocity changes from $3 Hz$ to $9 Hz$ in $3 s$ , what torque was applied to the object?

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Answer 1 · 2016-03-25T22:45:10

$294 N*m$

The torque is the product between the inertial momentum and the angular acceleration $tau = I* alpha$ .

As this case is single particle in a circular path $I =m*r^2$ and

$omega = (Delta omega)/(Deltat)$ , so

$tau= m*r*(Delta omega)/(Deltat) = 3kg*49m^2* (9Hz -3Hz)/(3sg) = 294 N*m$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 7 m7 m. If the object's angular velocity changes from 3 Hz 3 Hz to 9 Hz 9 Hz in 3 s3 s, what torque was applied to the object?