An object with a mass of 3 kg3kg is traveling in a circular path of a radius of 7 m7m. If the object's angular velocity changes from 6 Hz6Hz to 9 Hz9Hz in 3 s3s, what torque was applied to the object?

1 Answer
Nov 11, 2017

"923.6 Nm"923.6 Nm of torque was applied to object.

Explanation:

Torque is rate of change of angular momentum.

T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t

T = ("3 kg × (7 m)"^2 × 2 π (9 - 6) "Hz")/"3 s" = "923.6 Nm"