An object with a mass of $3 kg$ is traveling in a circular path of a radius of $7 m$ . If the object's angular velocity changes from $14 Hz$ to $17 Hz$ in $5 s$ , what torque was applied to the object?

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Answer 1 · 2017-10-08T14:28:03

The torque was $=554.2Nm$

The torque is the rate of change of angular momentum

$tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

The mass of the object is $m=3kg$

The radius is $r=7m$

For the object, $I=mr^2$

So, $I=3*(7)^2=147kgm^2$

And the rate of change of angular velocity is

$(d omega)/dt=(Deltaomega)/t=(34pi-28pi)/5=6/5pirads^-2$

So,

The torque is

$tau=147*6/5pi=554.2Nm$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 7 m7 m. If the object's angular velocity changes from 14 Hz 14 Hz to 17 Hz 17 Hz in 5 s5 s, what torque was applied to the object?