An object with a mass of $3 kg$ is traveling in a circular path of a radius of $7 m$ . If the object's angular velocity changes from $16 Hz$ to $17 Hz$ in $5 s$ , what torque was applied to the object?

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Answer 1 · 2017-01-12T07:31:09

The torque is $=184.7Nm$

The torque is the rate of change of angular momentum

$tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

The moment of inertia of the object is $I=mr^2$

$=3*7^2= 147 kgm^2$

The rate of change of angular velocity is

$(domega)/dt=(1)/5*2pi$

$=((2pi)/5) rads^(-2)$

So the torque is $tau=147*(2pi)/5 Nm=294/5piNm=184.7Nm$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 7 m7 m. If the object's angular velocity changes from 16 Hz 16 Hz to 17 Hz 17 Hz in 5 s5 s, what torque was applied to the object?