An object with a mass of $3 kg$ is traveling in a circular path of a radius of $6 m$ . If the object's angular velocity changes from $6 Hz$ to $17 Hz$ in $5 s$ , what torque was applied to the object?

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Answer 1 · 2017-11-11T02:03:19

$"1492.8 Nm"$ of Torque was applied to the object.

Torque is rate of change of angular momentum.

$T = (I(omega_f - ω_i))/t$

$= (I2pi(f_f - f_i))/t$

$= (mr^2 2pi(f_f - f_i))/t$

$= ("3 kg × (6 m)"^2 × 2 π (17 - 6) "Hz")/"5 s" = "1492.8 Nm"$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 6 m6 m. If the object's angular velocity changes from 6 Hz 6 Hz to 17 Hz 17 Hz in 5 s5 s, what torque was applied to the object?