An object with a mass of $3 kg$ is traveling in a circular path of a radius of $6 m$ . If the object's angular velocity changes from $6 Hz$ to $11 Hz$ in $5 s$ , what torque was applied to the object?

Question

1444 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-13T09:50:13

The torque was $=678.58Nm$

The torque is the rate of change of angular momentum

$tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

The moment of inertiai is $=I$

For the object, $I=(mr^2)$

So, $I=3*(6)^2=108kgm^2$

The rate of change of angular velocity is

$(domega)/dt=(11-6)/5*2pi$

$=(2pi) rads^(-2)$

So the torque is $tau=108*(2pi) Nm=678.58Nm$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 6 m6 m. If the object's angular velocity changes from 6 Hz 6 Hz to 11 Hz 11 Hz in 5 s5 s, what torque was applied to the object?