An object with a mass of 3 kg is traveling in a circular path of a radius of 6 m. If the object's angular velocity changes from 6 Hz to 14 Hz in 3 s, what torque was applied to the object?

1 Answer
Junaid Mirza
Nov 11, 2017

"1809.5 Nm"

Explanation:

Torque is rate of change of angular momentum.

T = (I(omega_f - ω_i))/t = (I2pi(f_f - f_i))/t = (mr^2 2pi(f_f - f_i))/t

T = ("3 kg × (6 m)"^2 × 2 π (14 - 6) "Hz")/"3 s" = "1809.5 Nm"

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