An object with a mass of $3 kg$ is traveling in a circular path of a radius of $3 m$ . If the object's angular velocity changes from $4 Hz$ to $7 Hz$ in $8 s$ , what torque was applied to the object?

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Answer 1 · 2017-11-11T01:36:27

$"63.6 Nm"$ of torque was applied to object.

Torque is rate of change of angular momentum.

$T = (I(omega_f - ω_i))/t$

$= (I2pi(f_f - f_i))/t$

$= (mr^2 2pi(f_f - f_i))/t$

$= ("3 kg × (3 m)"^2 × 2 π (7 - 4) "Hz")/"8 s" = "63.6 Nm"$

An object with a mass of 3 kg 3 kg is traveling in a circular path of a radius of 3 m3 m. If the object's angular velocity changes from 4 Hz 4 Hz to 7 Hz 7 Hz in 8 s 8 s, what torque was applied to the object?