An object with a mass of 3 kg is traveling in a circular path of a radius of 2 m. If the object's angular velocity changes from 3 Hz to 6 Hz in 5 s, what torque was applied to the object?

1 Answer
Feb 7, 2016

tau=72pi/5

Explanation:

tau=I* theta " torque"
theta=(Delta omega)/(Delta t)
theta=(2*pi*6-2.pi*3)
theta=1(2 pi-6 pi)/5
theta=(6 pi)/5
I=m*r^2=3*2^2=12
tau=12*(6 pi)/5
tau=72pi/5