An object with a mass of 3 kg is traveling in a circular path of a radius of 2 m. If the object's angular velocity changes from 2 Hz to 6 Hz in 5 s, what torque was applied to the object?

1 Answer
Jane
Jan 27, 2018

60.31 N.m

Explanation:

Torque (tau) is defined as change in rate of angular momentum i.e (dL)/dt or, (d(Iomega))/dt or, I (domega)/dt (as L=I omega, where, I is the moment of inertia)

So, I = mr^2

Given , m =3 Kg and r=2m

So, I= 12 Kg.m^2

Now (domega)/dt = ((nu 1-nu 2)/t)*2 pi i.e (6-2)/5*2pi (rad)/s^2

So, tau= (12*8/5 pi) N.m i.e 60.31 N.m

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