An object with a mass of $3 k g$ $3 kg$ is traveling in a circular path of a radius of $15 m$ $15 m$ . If the object's angular velocity changes from $25 H z$ $25 Hz$ to $28 H z$ $28 Hz$ in $9 s$ $9 s$ , what torque was applied to the object?

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An object with a mass of $3 k g$ $3 kg$ is traveling in a circular path of a radius of $15 m$ $15 m$ . If the object's angular velocity changes from $25 H z$ $25 Hz$ to $28 H z$ $28 Hz$ in $9 s$ $9 s$ , what torque was applied to the object?

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Answer 1 · 2016-04-02T12:01:15

Angular acceleration $α = \frac{ω_{f} - ω_{i}}{t} = 2 π (\frac{n_{f} - n_{i}}{t}) = 2 π \frac{28 - 25}{9} = \frac{2 π}{3} r a d s^{- 2}$ $alpha=(omega_f-omega_i)/t= 2pi((n_f-n_i)/t)=2pi(28-25)/9=(2pi)/3rads^-2$
Moment of inertia

$I = m r^{2} = 3 \times 15^{2} = 675 k g m^{2}$ $I=mr^2=3xx15^2=675kgm^2$

Torque
$τ = I \times α = 675 \times \frac{2 π}{3} = 450 π J$ $tau=Ixxalpha=675xx(2pi)/3=450pi J$

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An object with a mass of $3 k g$ $3 kg$ is traveling in a circular path of a radius of $15 m$ $15 m$ . If the object's angular velocity changes from $25 H z$ $25 Hz$ to $28 H z$ $28 Hz$ in $9 s$ $9 s$ , what torque was applied to the object?

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An object with a mass of 3kg 3 kg is traveling in a circular path of a radius of 15m15 m. If the object's angular velocity changes from 25Hz 25 Hz to 28Hz 28 Hz in 9s9 s, what torque was applied to the object?

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An object with a mass of $3 k g$ $3 kg$ is traveling in a circular path of a radius of $15 m$ $15 m$ . If the object's angular velocity changes from $25 H z$ $25 Hz$ to $28 H z$ $28 Hz$ in $9 s$ $9 s$ , what torque was applied to the object?