An object with a mass of $3 g$ is dropped into $50 mL$ of water at $0^@C$ . If the object cools by $5 ^@C$ and the water warms by $70 ^@C$ , what is the specific heat of the material that the object is made of?

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Answer 1 · 2017-04-06T10:32:36

The specific heat is $=976.7kJkg^-1K^-1$

The heat is transferred from the hot object to the cold water.

For the cold water, $Delta T_w=70ºC$

For the object $DeltaT_o=5ºC$

$m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)$

$C_w=4.186kJkg^-1K^-1$

Let, $C_o$ be the specific heat of the object

$0.003*C_o*5=0.050*4.186*70$

$C_o=(0.050*4.186*70)/(0.003*5)$

$=976.7kJkg^-1K^-1$

An object with a mass of 3 g3 g is dropped into 50 mL50 mL of water at 0^@C0^@C. If the object cools by 5 ^@C5 ^@C and the water warms by 70 ^@C70 ^@C, what is the specific heat of the material that the object is made of?