An object with a mass of $24 k g$ $24 kg$ is hanging from an axle with a radius of $24 m$ $24 m$ . If the wheel attached to the axle has a radius of $2 m$ $2 m$ , how much force must be applied to the wheel to keep the object from falling?

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Answer 1 · 2017-05-04T10:00:38

The force is $= 2822.4 N$ $=2822.4N$

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The load L=(24g)N#

Radius of axle $r = 24 m$ $r=24m$

Radius of wheel $R = 2 m$ $R=2m$

Taking moments about the center of the axle

$F \cdot R = L \cdot r$ $F*R=L*r$

$F \cdot 2 = 24 \cdot g \cdot 24$ $F*2=24*g*24$

$F = \frac{24 \cdot g \cdot 24}{2} = 2822.4 N$ $F=(24*g*24)/2=2822.4N$

An object with a mass of 24 kg24kg24 kg is hanging from an axle with a radius of 24 m24m24 m. If the wheel attached to the axle has a radius of 2 m2m2 m, how much force must be applied to the wheel to keep the object from falling?