An object with a mass of $2 kg$ is traveling in a circular path of a radius of $4 m$ . If the object's angular velocity changes from $2 Hz$ to $7 Hz$ in $2 s$ , what torque was applied to the object?

Question

1995 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-22T05:32:41

The torque is $=502.7m$

The torque is the rate of change of angular momentum.

$tau=(dL)/dt=(d(Iomega))/dt=I(domega)/dt$

$I=2*4^2=32kgm^2$

The rate of change of angular velocity is

$(domega)/dt=(7-2)/2*2pi$

$=5pi rads^(-2)$

So the torque is $tau=32*5pi Nm=502.7Nm$

An object with a mass of 2 kg 2 kg is traveling in a circular path of a radius of 4 m4 m. If the object's angular velocity changes from 2 Hz 2 Hz to 7 Hz 7 Hz in 2 s 2 s, what torque was applied to the object?