An object with a mass of $2 kg$ is traveling in a circular path of a radius of $4 m$ . If the object's angular velocity changes from $1 Hz$ to $12 Hz$ in $2 s$ , what torque was applied to the object?

Question

2190 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-04T18:30:13

$T=352pi " "N*m$

$m=2" "kg" mass of object"$

$r=4" "m " radius of the circular path"$

$f_1=1" "Hz" initial frequency of object"$

$f_2=12" "Hz" final frequency of object"$

$Delta t=2" "s$

$F=m*a " Newton equation for linear motion"$

$T=I*alpha" Newton equation for rotary motion"$

$T " represents Torque of object"$

$I " represents the moment of inertia of the object"$

$alpha " represents angular acceleration of the object"$

$alpha=(omega_2-omega_1)/(Delta t)$

$"the angular velocity of an object is expressed as "omega=2*pi*f$

$alpha=(2*pi(f_2-f_1))/2=pi(f_2-f_1)=pi(12-1)=11pi$

$I=m*r^2=2*4^2=32$

$T=32*11pi$

$T=352pi " "N*m$

An object with a mass of 2 kg 2 kg is traveling in a circular path of a radius of 4 m4 m. If the object's angular velocity changes from 1 Hz 1 Hz to 12 Hz 12 Hz in 2 s 2 s, what torque was applied to the object?