An object with a mass of 2 kg2kg is traveling in a circular path of a radius of 4 m4m. If the object's angular velocity changes from 1 Hz1Hz to 3 Hz3Hz in 2 s2s, what torque was applied to the object?

1 Answer
Feb 13, 2016

L=64piL=64π

Explanation:

alpha=(Delta omega)/(Delta t)
"alpha is the angular acceleration for object"
alpha=(2pi*f_f-2pi*f_i)/2
alpha=(2pi*3-2pi*1)/2
alpha=4pi/2
alpha=2pi
"L:torque"
L=alpha*I
"I=m*r^2
L=2pi*2*4^2
L=64pi