An object with a mass of 2 kg2kg is traveling in a circular path of a radius of 4 m4m. If the object's angular velocity changes from 1 Hz1Hz to 2 Hz2Hz in 2 s2s, what torque was applied to the object?

1 Answer
Feb 13, 2016

L=32piL=32π

Explanation:

"the angular acceleration of a rotating object is given by: "the angular acceleration of a rotating object is given by:
alpha=(Delta omega)/(Delta t)
alpha=(cancel(2)pi(f_f-f_i))/cancel(2)
alpha=pi(2-1)
alpha=pi
"Torque for an object making rotary motion is given as:"
L=alpha*I
"we can write " m*r^2 " instead I"
L=alpha* m*r^2
L=pi*2*4^2
L=32pi