An object with a mass of $2 k g$ $2 kg$ is traveling in a circular path of a radius of $4 m$ $4 m$ . If the object's angular velocity changes from $1 H z$ $1 Hz$ to $6 H z$ $6 Hz$ in $3 s$ $3 s$ , what torque was applied to the object?

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An object with a mass of $2 k g$ $2 kg$ is traveling in a circular path of a radius of $4 m$ $4 m$ . If the object's angular velocity changes from $1 H z$ $1 Hz$ to $6 H z$ $6 Hz$ in $3 s$ $3 s$ , what torque was applied to the object?

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Answer 1 · 2017-04-09T18:00:11

88N

Explanation:

first we need to find out the change in instantaneous velocity .
which is from 1 Hz to 6 Hz using formula
$ω$ $omega$ = $\frac{2 π R}{T} = v R$ $(2 piR)/T=vR$
$\Rightarrow v = 2 \frac{π}{T}$ $=>v=2pi/T$
substituting values of 1 Hz as $\frac{1}{ν} = T$ $1/nu=T$
we get the values for instantanious velocity for 2 cases of 1 Hz and
6 Hz as 6.28 $m s^{- 1}$ $ms^(-1)$ and $39.26 m s^{- 1}$ $39.26ms^(-1)$
we use the Newton's law of motion according to which
$v = u + a \cdot t$ $v=u+a*t$
substituting
u=6.28
v=39.26
and T=3
We get the value for 'a' Acceleration as 10.99 $≅$ $~=$ 11 $m s^{- 1}$ $ms^(-1)$
For torque = $m \cdot a \cdot R$ $m*a*R$
we substitute desired values and get 88 N

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An object with a mass of $2 k g$ $2 kg$ is traveling in a circular path of a radius of $4 m$ $4 m$ . If the object's angular velocity changes from $1 H z$ $1 Hz$ to $6 H z$ $6 Hz$ in $3 s$ $3 s$ , what torque was applied to the object?

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Explanation:

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An object with a mass of 2 kg2kg 2 kg is traveling in a circular path of a radius of 4 m4m4 m. If the object's angular velocity changes from 1 Hz1Hz 1 Hz to 6 Hz6Hz 6 Hz in 3 s3s 3 s, what torque was applied to the object?

1 Answer

Explanation:

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An object with a mass of $2 k g$ $2 kg$ is traveling in a circular path of a radius of $4 m$ $4 m$ . If the object's angular velocity changes from $1 H z$ $1 Hz$ to $6 H z$ $6 Hz$ in $3 s$ $3 s$ , what torque was applied to the object?